Day#7 [ 21 Days — C Programming ]

Switch-Case Statement :

Most of the beginners stuck at this point , they didn’t understand what actually switch-case is doing and where we should prefer switch case over if-else .

But don’t worry I will tell you everything you need to know about switch-case , let’s relax your mind .

First of all let’s see how switch case looks like : ( Pseudo Code )

switch(condition) {

case condition1 :

print(“condition1 statement”)

break

case condition2 :

print(“condition2 statement”)

break

default :

print(“default statement”)

}

so when the condition inside switch and case’s condition is same that case is going to be executed if no case condition meets then default case will be executed .

( Remember this is default only not default case or case default )

you can see these case are in linear .

case1 -> case2 -> default

so if you don’t use break then after case1, case2 and default will also get executed , so be aware of using break , sometime it is good to use break wisely like :

case ‘a’:

case ‘A’:

print(“Alphabet A”)

break;

so in this if switch condition is ‘a’ or ‘A’ it will print Alphabet A .

( Remember to use break wisely )

Now let’s see some example :

Example-1:

#include<stdio.h>

void main() {

int x = 1;

switch(x) {

case 1:

printf(“case1 executed.”);

break;

case 2:

printf(“case2 executed.”);

break;

default:

printf(“default case executed.”);

}

}

Output

case1 executed.

Explanation

since switch condition is 1 so case 1 will be executed and break statement will take it out .

Example-2:

#include<stdio.h>

void main() {

int x = 1;

switch(x) {

case 1:

printf(“case1 executed.”);

case 2:

printf(“case2 executed.”);

default:

printf(“default case executed.”);

}

}

Output

case1 executed.

case2 executed.

default case executed.

Explanation

since switch condition is 1 so case 1 will be executed but there is no break so it will run all cases .

Example-3:

#include<stdio.h>

void main() {

switch((1+1)/2+1) {

case 1:

printf(“case1 executed.”);

break;

case 2:

printf(“case2 executed.”);

break;

default:

printf(“default case executed.”);

}

}

Output

case2 executed.

Explanation

(1+1)/2+1 = 2/2+1 = 1 + 1 = 2

so switch condition is 2 so case 2 will be executed and break will take it out .

Example-4:

#include<stdio.h>

void main() {

switch(2) {

case 1:

printf(“case1 executed.”);

break;

case 1+1:

printf(“case1+1 executed.”);

break;

default:

printf(“default case executed.”);

break;

}

}

Output

case1+1 executed.

Explanation

case1+1 is same as case2 so for switch(2) case 1+1 will be executed.

Example-5:

#include<stdio.h>

void main() {

switch(2) {

case 1:

printf(“case1 executed.”);

break;

case 1+1:

printf(“case1+1 executed.”);

break;

case 2:

printf(“case2 executed.”);

break;

default:

printf(“default case executed.”);

break;

}

}

Output

Compilation Error

5_switch.c:10:3: error: duplicate case value

10 | case 2:

| ^~~~

5_switch.c:7:3: note: previously used here

7 | case 1+1:

| ^~~~

Explanation

Duplicate cases are not possible .

Since case1+1 and case2 are same so compiler will give you error .

I think I have covered all points by these 5 examples .

Thank you …

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Vikas Shekhawat

Vikas Shekhawat

Software engineer and a happy 😊 person .

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